November 09, 2026, 07:21:36 pm

Author Topic: Mathematics ?  (Read 152 times)

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Offline taha

Re: Mathematics ?
« Reply #20 on: October 23, 2012, 05:13:55 pm »

 {x^2-y^2=5
 {x+y=9

so easy !!!11!!!!
{x^2-y^2=5
{x+y=9

{(x-y)(x+y)=5
{y=9-x

{[x-(9-x)](x+9-x)=5
{y=9-x

{9*(x-9+x)=5
{y=9-x

{9x-81+9x=5
{y=9-x

{18x=86               {x=86/18
{y=9-x          <=> {y=9-(86/18)

{x=86/18   
{y=162/18       so S={86/18,162/18}

thank you based god !!11!1!

Offline 'PL'

Re: Mathematics ?
« Reply #21 on: October 23, 2012, 05:53:48 pm »
Prove that
1/[lg(x)a * log(x)a^2] + 1/[lg(x)a^2 * lg(x)a^3] + ... + 1/[log(x)a^n-1 * lg(x)a^n] = n-1/[n] * (log(a)x)^2
Solve that,
Took me 5 hours solving this =D

Offline Jonathan

Re: Mathematics ?
« Reply #22 on: December 26, 2012, 10:37:08 pm »
Here is a Math Question That i did in a exam :

Fred is A farmer and he got 10 chicken , if one chicken make 2 eggs per day and fred add 1 new chicken every 2 weeks , how many times does he eat bacon on breakfast ?  ;D
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Offline 'PL'

Re: Mathematics ?
« Reply #23 on: December 27, 2012, 02:15:48 am »
10 Chickens
1 Chicken - (+ 2 eggs)
+1 Chicken - (+2 weeks) = 7x2 = 14 days
Breakfast - 1 day
Beacon - ?

trAB=trBA
:D
(Quantum physics time)


Daniel

  • Guest
Re: Mathematics ?
« Reply #24 on: December 28, 2012, 06:34:59 am »
Prove that
1/[lg(x)a * log(x)a^2] + 1/[lg(x)a^2 * lg(x)a^3] + ... + 1/[log(x)a^n-1 * lg(x)a^n] = n-1/[n] * (log(a)x)^2
Solve that,
Took me 5 hours solving this =D
Induction would solve this in 1 min!

Offline taha

Re: Mathematics ?
« Reply #25 on: December 29, 2012, 01:15:19 pm »
Prove that
1/[lg(x)a * log(x)a^2] + 1/[lg(x)a^2 * lg(x)a^3] + ... + 1/[log(x)a^n-1 * lg(x)a^n] = n-1/[n] * (log(a)x)^2
Solve that,
Took me 5 hours solving this =D
Induction would solve this in 1 min!
^this.

thank you based god !!11!1!